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18a^2+27a+4=0
a = 18; b = 27; c = +4;
Δ = b2-4ac
Δ = 272-4·18·4
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-21}{2*18}=\frac{-48}{36} =-1+1/3 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+21}{2*18}=\frac{-6}{36} =-1/6 $
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